Question

need help on the attachment @MIT 18.01 Single …

Answer 1

Since that's a velocity vs time graph, integrate geometrically to find distance traveled from time t=3 to t=7. Add that distance to 50 yards.

Answer 2

still not sure how to that

Answer 3

???

Answer 4

Something seems wrong. Even traveling at 6 yd/s the entire way through there is no way he got to any of those distances.
What are the units on the graph?

Answer 5

if you approximate the squares from t=0-3 you get 4.5 which means each square is 10 units

Answer 6

multiply your answer by 10 xavier

Answer 7

1square = 10 yards

Answer 8

Ah got it, he has been traveling before t=3.

Answer 9

hmm???

Answer 10

So knowing each box is 10 yards, find the area between t=3 and t=7 by making triangles and other shapes. Add this value to 50

Answer 11

Xavier, I wouldn't use triangles everything can be made into rectangles

Answer 12

in which you can use the diagonal to explain that each half is equal

Answer 13

so do I need count all the square between t=3 and t=7

Answer 14

But there is that region above like t=5 where the square isn't cut in half. In any case, whatever works to find area

Answer 15

yeah split from t4-t7 into two regions

Answer 16

a perfect rectangle and the triangle, make a rectange with the triangle that the diagonal is the function and you divide by 2

Answer 17

what about if the student walk for t0 to t10

Answer 18

answer is 190 i mean

Answer 19

just added wrong i have no calculator... 50+20+60+60

Answer 20

distance from 0-10 = 200

Answer 21

answer choices are
1. dist = 250 yards
2. dist = 220 yards
3. dist = 230 yards
4. dist = 270 yards
5. dist = 240 yards

Answer 22

the answer choices are for the t0 to t10 question that you got 200 for

Answer 23

??

Answer 24

Outkast3r09 are you still there?