how do you solve x^2-14x+49=9 by using the square root property?

Question

myininaya · Answer

$$\text{   recall   } x^2-14x+49=(x-7)^2$$

myininaya · Answer

use that and have fun

myininaya · Answer

look at the previous one i did for you and ask any questions but you should try this one on your own
and i will totally check if you like

anonymous · Answer

Notice how x^2, 9 and 49 are perfect squares? This will come in handy:

First, factor the left hand side by looking for two numbers that add up to -14 and multiply to 49 (these two numbers are -7 and -7)

so you get $$(x-7)^2=9 $$ square root both sides and solve for x:
$$x-7=3$$$$x=10$$

myininaya · Answer

plus or minus  3 right junkie?

anonymous · Answer

Yeah, just noticed that there should be two solutions

myininaya · Answer

$$x-7=\pm 3$$

anonymous · Answer

why is it -14 thouqh ?

anonymous · Answer

oh nevermind iget why . THankyou !

anonymous · Answer

well when you factor a quadratic function you generally have the form : $$x^2+ax+b$$and you look for two numbers (c & d) that satisfy the following two equations:$$c+d=a$$$$c*d=b$$c and d then get plugged into this guy: $$(x+c)(x+d)$$

anonymous · Answer

Ohhhhh okay ! :D