Question

Perform the indicated operation.

Write the result in the form a + bi.

i13

Answer 1

Is this \[\Large i^{13}\] ???

Answer 2

yes

Answer 3

\[\Large i^{13}\]


\[\Large i^{12+1}\]


\[\Large i^{12}*i^{1}\]


\[\Large (i^{4})^3*i^1\]


\[\Large (1)^3*i\]


\[\Large (1)i\]


\[\Large i\]


So \[\Large i^{13}=i\]

Answer 4

what about when it says write it in a+bi form?

Answer 5

It's in that form because i = 0 + 1i


Note: a = 0 and b = 1

Answer 6

ok, thanks so much!

Answer 7

np