Question

Find the complex zeros of f:

f(x)=-x^2+x-1

Find the complex zeros of f:

f(x)=-x^2+x-1

@Mathematics

Answer 1

\[x= \sqrt[3]{-1};x=-(-1)^{2/3}\]

Answer 2

How is that?

Answer 3

quadratic formula

Answer 4

How do you get that answer?

Answer 5

a = -1, b = 1, c = -1

x = (-1 +- sqrt(-3))/2 = (-1 +- i*sqrt3)/2

Answer 6

whoops, it's supposed to be -2 on the bottom :)

Answer 7

\[x=\frac{ -1 \pm \sqrt {1-4(-1)(-1)}}{2(-1)} = \frac{-1 \pm \sqrt{-3}}{-2}\]\[=\frac{1}{2} \pm \frac{\sqrt{3} i}{-2}\]