ABC is a triangle in which AC = 12.7cm, BC=16.5cm and ACB Is a right-angle. BD is a straight line 13.4 cm long, making an angle of 28 degrees with BC. The foot of the perpendicular from D onto AB is the point marked E. @Mathematics
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what is the question?
Sorry! Calculate the length of BE.
BE = 12.2
How? Please explain :)
using the length of BC and AC you can find the length of AB. Then, using trig, you can find the angle ABC. Add that to the Angle CBD and you have the ange ACD. Using that and the length bD you can use trig to get the length of BE
are you okay with the trig?
I was actually stuck on the trigonometry bit!
tanA = 16.5/12.7, so the measure of angle A if 52.4 degrees. Than makes angle ABC 37.5 degrees and angle D 24.4 degrees. So angle ABD is 52.4 degrees also. Now BE/13.4 = cos 24.4 Solve for BE by multiplying cos 24.4 by 13.4.
Thank you so much Mertsj! And thank you so much also mathstudent!
yw
no problem and good luck!
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