Question

64^(3/4)

Answer 1

show work please

Answer 2

\[\sqrt[4]{64^{3}}\]
\[\sqrt[4]{262144}\]\[\approx22.627\]

Answer 3

i need the exact answer though. not an approximate...

Answer 4

and i jsut cant remember how to evaluate it

Answer 5

64^(3/4) = the fourth root of 64^3
262,144 = 64^3
the fourth root of 262,144 is about 22.6374

Answer 6

thats not an exact answer. the exact answer is \[16\sqrt{2}\] but i have no idea how to get there.

Answer 7

or: \[\sqrt[4]{262144} = \sqrt{512} = 16\sqrt{2}\]

Answer 8

you're right

Answer 9

how did you get it. those are just numbers under a radical. i dont know how to get to the \[\sqrt{512}\] or anything. im so lost on how to break it down.

Answer 10

alright on the \[\sqrt[4]{262144}\] part, if you take the square root of 262144, you get a square root problem. The squaret root of 262144 is 512 so you get \[\sqrt{512}\]
512 = 2*16*16 so \[\sqrt{512}\]= \[\sqrt{2*16*16}\]
The square root of 16 is 4 so if you pull the 16s outside, you get
\[4*4\sqrt{2}\]
or
\[16\sqrt{2}\]

Answer 11

detail on the first part
\[\sqrt[\sqrt{4}]{\sqrt{262144}}=\sqrt{512}\]

Answer 12

so basically I took the square root of the outside and the inside of the radical.

Answer 13

\[\sqrt[4]{(64)^{3}}=\sqrt[4]{((2})^{6})^{3}=\sqrt[4]{2^{18}}=\sqrt[4]{(2^{4})^{4}*2^{2}}=\]

Answer 14

\[2^{4}\sqrt[4]{2^{2}}=16\sqrt[4]{4}\]

Answer 15

hope so much that now will be understandably sure