There is a 0.63 probability that Mobil stock will rise, a 0.75 probability Gulf stock will rise and a 0.4 chance that both stocks will rise. Find the probability that neither stock will rise. There is a 0.63 probability that Mobil stock will rise, a 0.75 probability Gulf stock will rise and a 0.4 chance that both stocks will rise. Find the probability that neither stock will rise. @Mathematics
So .37*.25=.0925 But the answer key for a similar problem( only difference is .47 instead of .4), the answer is .2775. The answers shouldnt differ that much right?
why are you multiplying those two numbers?
isnt that how you get the probability for AND?
not in this case
Then Im completely lost.
your events are NOT independent
I think that's the concept that I dont quite understand
would the formula be P(A U B)/P(A)?
no
use \[P(A^c\cap B^c)=1-P(A\cup B)\]
so the 1-P(none) formula
for any event E \[P(E)=1-P(E^c)\] or \[P(E^c)=1-P(E)\]
so how exactly does not being independent effect the problem?
events A and B are independent iff \[P(A\cap B)=P(A)P(B)\]
you cant use this formula since A and B are not independent
So in terms of a venn diagram, independent is two circles that dont intersect. and not independent has two circles that do intersect. and in this problem the intersection is .4? So I need to find the sum of each part of the venn diagram, subtract from one (to get the number outside the diagram) which would be the "neither". Correct?
NO
independent events intersect (most of the time)
if A and B are independent and P(A)>0 and P(B)>0 then A and B have to intersect.
use \[P(A^c\cap B^c)=1-P(A\cup B)=1-[P(A)+P(B)-P(A\cap B)]\]
|dw:1321204843404:dw| Is what Im picturing Basically, I was doing P(Ac∩Bc)=1−P(A∪B)=1−[P(A)+P(B)−P(A∩B)] except that mine adds instead of subtracts the intersection.
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