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could someone help me find antiderivaative of 5/x^4
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\[\int \frac{5}{x^4}\space dx=-\frac{5}{3x^3}+C\]
know that 5/x^4=5x^(-4)
could you explain the steps to find that
\[\int\frac{5}{x^4}dx=5\int\frac{1}{x^4}dx=5\int x^{-4}dx=5(3x^{-3})+C=\frac{5}{3x^3}+C\]
hmm...okay i think i kinda see it
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I left off a negative sign when I took the integral of x^-4...
should be 5 \integral x^-4 dx = 5(-3x^-3) = - 5/(3x^3)+C I switched to the negative exponents because it makes it a bit easier, like doing a regular exponent... I don't generally do that so I tend to mess it up.
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