What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
?
why isn't it \[20!\]?
oh i see why never mind
1745944200, though it seems awfully large
I was thinking about it backwards
its\[2^4\cdot3^2\cdot5\cdot7\cdot11\cdot13\cdot17\cdot19\]
\[20! = 2.43290200817664 × 10^18\]
232792560
ok you know you need \[2,3,5,7,13,17,19\] as factors, now lets see what powers you need. need \[2^4\] to get 16 need \[3^2\] to get 9, and i think that is it because \[5^2=25\] too big, so i am going to say \[2^4\times 3^2\times 5\times7\times 13\times 17\times 19\]
dont forget 11 satellite :)
aaaand joemath hits the jackpot.
i will let joemath correct me if i am wrong.
\[2^4\times 3^2\times 5\times7\times 11\times 13\times 17\times 19\]
forgot one didn't i
the idea was right though. just look and see what powers of primes are included from 1 to 20.
oh wow i didn't see you had the answer miles above...
no one see's my posts =/ lolol jk
@across - I thought you said "evenly divisible"? 232792560 / 17 = 14549535 which is not an even number?
I missed the powers of primes part :(
by evenly divisible, i understood it as "no remainder"
That's how I took it
sorry I meant 232792560 / 16 = 14549535
Even divisibility often implies a division leaving no remainder.
ok - my misunderstanding then.
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