Let f be a 1-1 function such that f(a) = b, f(b) = c, and f(c) = a. Find the following. f −1(f −1(c))
deja vu
i tryied asking you to explain more tryign to get it
oh ok we take it one step at at time
thank you
we know \[f(a)=b\] so we also know that \[f^{-1}(b)=a\] so far ok?
yes
also we have \[f(b)=c\] so we know \[f^{-1}(c)=b\] right?
yes
so what does \[f^{-1}(f^{-1}(c))\] mean? it means first find \[f^{-1}(c)\] and then find \[f^{-1}\] of the result
so writing it out we get \[f^{-1}(f^{-1}(c))=f^{-1}(b)\] and that is true because we know \[f^{-1}(c)=b\]
next step is \[f^{-1}(b)=a\] which we also knew from above
writing this in one line we get \[f^{-1}(f^{-1}(c))=f^{-1}(b)=a\] and that is what you wanted
make sense or still confusing?
okay i am getting it..so the answer is simple a or do i write if F-1(b)+a
no answer is simply "a"
there is no "+" involved
meant = sorry
sweet thank you i am pretty sure i get it now
oh ok, the answer is just "a"
for example if you know \[2x-1=7\] then you know that \[x=4\] this is like saying \[f(x)=2x-1\] and \[f(4)=7\] \[f^{-1}(7)=4\]
okay cool thank you
yw
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