Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

A certain chain of ice cream stores sells 28 different flavors, and a customer can order a single-, double- , or triple-scoop cone. suppose on a multiple-scoop cone that the order of the flavors matter and that the flavors can be repeated.how many possible cones are there?

OpenStudy (mertsj):

28^3+28^2+28

OpenStudy (anonymous):

THANK YOU!!! :D

OpenStudy (mertsj):

yw

OpenStudy (anonymous):

can you explain how you knew to do tht?

OpenStudy (mertsj):

Think about the cones with only 1 scoop of ice cream. Isn't it clear that there are 28 of those? Now think about the two scoop cones. You have 28 choices for the first scoop and 28 choices for the second scoop. So the number of possibilities is 28(28). Now think of the 3 scoop cones. You have 28 choices for the first scoop, 28 choices for the second scoop, and 28 choices for the third scoop or 28(28)(28) possibilities. Add them all together and you have the total.

OpenStudy (anonymous):

ohhh ok...thanks.

OpenStudy (anonymous):

what if the order of flavors doesn't matter?

OpenStudy (mertsj):

Divide 28^3 by 3 factorial. Divide 28^2 by 2 factorial

OpenStudy (anonymous):

why?

OpenStudy (mertsj):

To divide out the duplicates.

OpenStudy (anonymous):

what is the number of double-scoop ice cream cones that are possible if repetition of flavors is allowed but the order of flavors is unimportant?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!