Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

anyone have a quick simple explanation of eigenvalues and eigenvectors?

OpenStudy (amistre64):

quick and simple eh, not me. I just started reading up on these myself

OpenStudy (amistre64):

the eugne values are of the form: \[\left|\begin{array}c \lambda_1&0&0\\ 0&\lambda_2&0\\ 0&0&\lambda_3\\ \end{array}\right|\]

OpenStudy (amistre64):

i think you cross the eugene with the given matrix and solve for a zero determinant

OpenStudy (amistre64):

or is it subtract?

OpenStudy (turingtest):

Basically an eigenvalue is a number that alters a vector x in the same way as some given matrix A would.\[Ax=\lambda x\]where x is the eigenvector of A and lambda is the eigenvalue of A. http://tutorial.math.lamar.edu/Classes/LinAlg/EVals_Evects.aspx

OpenStudy (amistre64):

\[\left|\begin{array}c 3-\lambda_1&1&2\\ 3&5-\lambda_2&3\\ 0&1&1-\lambda_3\\ \end{array}\right|\]

OpenStudy (turingtest):

right, \[(A-\lambda I)x=0\]then do the determinant and solve for lambda.

OpenStudy (turingtest):

but there is only one value lambda amistre, not three. No subscript is needed

OpenStudy (turingtest):

taking the determinant gives you a quadratic equation which can be solved for lambda

OpenStudy (amistre64):

..... one lambda is definately better to solve than 3 ;)

OpenStudy (turingtest):

definately :)

OpenStudy (amistre64):

taking the linear algebra next term , yay!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!