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Mathematics 8 Online
OpenStudy (anonymous):

one cycle of sine function begins at x= - pi/6 and ends at pi/3, determine the period?

OpenStudy (maya):

pi/3- (-pi/6) is your period

OpenStudy (maya):

Your last point minus first point = period of the curve

OpenStudy (anonymous):

oh okay the back of my textbook says pi/2

OpenStudy (maya):

That is correct..common dem will give you 2pi/6 - (-pi/6) = 2pi/6 +p/6

OpenStudy (maya):

that is equal to 3pi/6= pi/2

OpenStudy (anonymous):

didnt you say you have to add the last point by the first point.. with would be pi/3+(-pi/6) ?

OpenStudy (maya):

You add when you have to find the midpoint. So you would add one point with another and divide it by 2 to get the middle point of the two.

OpenStudy (maya):

But when you have to find the period, it is last point minus first

OpenStudy (anonymous):

oh okay, and to get the period you would subtract the last point by the first point right

OpenStudy (maya):

Yes!

OpenStudy (anonymous):

ohh okay, and to get the phase shift, what do u do

OpenStudy (maya):

And you can also use 2pi/b = period

OpenStudy (maya):

You mean how to get the x-value given the phase shift?

OpenStudy (anonymous):

the question ask, determine the phase shift of the function

OpenStudy (maya):

Are you given the sketch of the function?

OpenStudy (anonymous):

what i did, was subtract the lat point by the first point, and i got the right answer, would that be right

OpenStudy (maya):

for the phase shift?

OpenStudy (anonymous):

i mean i added the last point by the first point

OpenStudy (anonymous):

ya for the phase shift

OpenStudy (maya):

hmm

OpenStudy (anonymous):

for the phase shift, what i did was, add the last point by the first point.. and i got the right answer, so im wondering if i did that right, and no i wasnt given a graph

OpenStudy (maya):

oh ok

OpenStudy (anonymous):

im still trying to figure out the period and what i got was 3pi/6.

OpenStudy (maya):

draw the regular sine curve and see how the x values differ from the original points. Remember how we did that today?

OpenStudy (maya):

3pi/6 is right. reduce it to pi/2

OpenStudy (anonymous):

ohh okayy

OpenStudy (anonymous):

okay i have one more question

OpenStudy (anonymous):

what did u say the k in the equation y=sin[k(x-d)] meant

OpenStudy (maya):

So for example, if the first transformed point is (1/4,0) then it means there is a phase shift of 1/4 to the right. Understand?

OpenStudy (maya):

The "k" is the "b" which we were referring to when trying to figure out the period. For example, 2pi/k = period of the sine/ cos curve

OpenStudy (anonymous):

so in the equation would we put the period where k is

OpenStudy (maya):

No, so since you know the period which is pi/2, you can use the above formula and figure out what k is. 2pi/k = period so k= 2pi/period that is what you put in for the k value

OpenStudy (anonymous):

ohhh okay thank you

OpenStudy (anonymous):

and when it says graph the function over 2 periods,, what do we continue the graph until. 4pi?

OpenStudy (maya):

If the period is pi then you continue it until 2pi it order to cover 2 cycles. If the period is 2/pi then 2 cycles would be 4/pi not 4pi.

OpenStudy (anonymous):

ohh okay thank you

OpenStudy (maya):

np

OpenStudy (anonymous):

ill see you on wed. bye

OpenStudy (maya):

alright. see ya. Good luck! And bring your test with you if you get it back so we can look it over.

OpenStudy (anonymous):

okayy

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