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3log3 6 = 6... how is this?
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\[3\log_{3} 6=6\] ?? how do they get 6?
3log36 can be written as log36^3 log3216
You are right it doesn't make sense
wait..
\[3^\log_{3} 6 = 6\]
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it is wrong that is why
maybe \[3^{\log_3(6)}=6\] that is true
yes
i cant get my equation to do that. how do u arrive at 6 please?
true because \[\log_3(6)\] is an exponent. it is what you would raise 3 to in order to get 6 so when you raise 3 to that power, you get 6 by definition
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also true because as function \[3^x\] and \[\log_3(x)\] are inverses so when you compose them you get x back
hmm so \[\log_{3} 6 \neq 2\]
3* 2 =6 , thats why its 2
so is this a logarithmic identity? \[a ^{\log_ax} = x\] ??
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