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Mathematics 7 Online
OpenStudy (anonymous):

3log3 6 = 6... how is this?

OpenStudy (anonymous):

\[3\log_{3} 6=6\] ?? how do they get 6?

OpenStudy (anonymous):

3log36 can be written as log36^3 log3216

OpenStudy (anonymous):

You are right it doesn't make sense

OpenStudy (anonymous):

wait..

OpenStudy (anonymous):

\[3^\log_{3} 6 = 6\]

OpenStudy (anonymous):

it is wrong that is why

OpenStudy (anonymous):

maybe \[3^{\log_3(6)}=6\] that is true

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i cant get my equation to do that. how do u arrive at 6 please?

OpenStudy (anonymous):

true because \[\log_3(6)\] is an exponent. it is what you would raise 3 to in order to get 6 so when you raise 3 to that power, you get 6 by definition

OpenStudy (anonymous):

also true because as function \[3^x\] and \[\log_3(x)\] are inverses so when you compose them you get x back

OpenStudy (anonymous):

hmm so \[\log_{3} 6 \neq 2\]

OpenStudy (anonymous):

3* 2 =6 , thats why its 2

OpenStudy (anonymous):

so is this a logarithmic identity? \[a ^{\log_ax} = x\] ??

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