Question

How do i get this error hes talking about heres my code.

def printTwice(bruce):
print bruce, bruce

def catTwice(part1, part2):
cat = part1 + part2
printTwice(cat)

chant1 = "Pie Jesu domine, "
chant2 = "Dona eis requiem."
catTwice(chant1, chant2)

If an error occurs during a function call, Python prints the name of the function, and the name of the function that called it, and the name of the function that called that, all the way back to __main__.

For example, if we try to access cat from within printTwice, we get a NameError:

Traceback (innermost last):
Fil

Answer 1

For example, if we try to access cat from within printTwice, we get a NameError:

Traceback (innermost last):
File "test.py", line 13, in __main__
catTwice(chant1, chant2)
File "test.py", line 5, in catTwice
printTwice(cat)
File "test.py", line 9, in printTwice
print cat
NameError: cat

Answer 2

I think he means something like this:

def printTwice(bruce):
print cat, cat

def catTwice(part1, part2):
cat = part1 + part2
printTwice(cat)

You can't refer to "cat" from printTwice() because it's defined in another function. (Actually, there's just nothing called "cat" that's accessible from the scope inside of printTwice(). You'd get the same error if you tried "print foo, foo" because there's no "foo" variable, either.)