Find bases for the four fundamental subspaces of the Matrix A. V1=(1,0,2),V2=(1,1,0),V3=(-1,0,-1) Need answer Find bases for the four fundamental subspaces of the Matrix A. V1=(1,0,2),V2=(1,1,0),V3=(-1,0,-1) Need answer @Mathematics
just so you don't get the matrix messed up, those are column vectors. I'm not sure how to put in a 3x3 matrix
for Rank, did you basically get the standard basis for R3?
well you can see they are all dependent so it could be the originals vectors but i like nicer numbers
I think you mean to say independent
\[R(A^T)=(1,0,0)^T,(0,1,0)^T,(0,0,1)^T\] and i mean't columnspace
You cannot write the other vectors in the form of others therefore they're all dependent
you have dependent and independent backwards
We just went over some of this stuff tonight in Linear Algebra... not far enough along yet to answer your questions, but I can help with the matrix... if they are column vectors, the matrix should be: [ 1 1 -1 ] [ 0 1 0 ] [ 2 0 -1 ]
ahh yeah i just noticed that
I thought I was going to be able to do that with the editor but it didn't work, but that should work, but I just saw you meant column space, so I guess that's not what you meant anyway :P
\[\left[\begin{matrix}1 & 1&-1 \\0 & 1&0 \\ 2 & 0&-1 \end{matrix}\right]\]
right click on my matrix and view source to see what I did.
'show source'
so did you get the same for the transpose of the columnspace and the columnspace
are you looking for a basis for A and A transpose?
Its Zarkon! awesome :)
Hi joe :)
i'm looking for the four fundamentals, so the Column spaces and nullspaces of Matrix A and it's transpose
it is me
awesome!
the matrix has full rank (and it is square) so the null space is just the zero vector
yeah that's what i was assuming but you got the standards for the column spaces?
The the null space of A transpose will also be just the 0 vector, as the rank of A is the same as the rank of A transpose.
use the originals if you want
they are L.I.
So this problem is that bad. All the columns form a basis for the Col Space, all the rows form a basis for the Row Space, and the Null Space and Left Null Space are trivial.
isnt* i meant isnt >.> lol
That's why i asked for the answers lolz XD it's on my pretest that my teacher gives no answers
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