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Biology 25 Online
OpenStudy (anonymous):

A normal appearing couple is found to be heterozygous recessive for albinism. Both have the genotype Aa. The gene responsible for albinism is recessive to the normal pigment-producing gene. What are the chances of their children being albino? a. 3:4 children will be albino. b. All children will be albino. c. 1:4 children will be albino. A normal appearing couple is found to be heterozygous recessive for albinism. Both have the genotype Aa. The gene responsible for albinism is recessive to the normal pigment-producing gene. What are the chances of their children being albino? a. 3:4 children will be albino. b. All children will be albino. c. 1:4 children will be albino. @Biology

OpenStudy (anonymous):

3:1

OpenStudy (anonymous):

heena's diagram shows you the right solution on how to solve this problem. It shows that there is 4 chances to see their kids' genomic combinations. 2 out of 4 possibilities of which their kids are completely normal and not a recessive carrier, 1 out of 4 possibility where their kid will be normal but is a carrier of the recessive albinism 1 out of 4 possibility where the kid will be an albino. Ratio-wise, the answer is: c. 1:4 children will be albino

OpenStudy (anonymous):

Consider the following cross: Parent 1: YyTt Parent 2: YyTt Using the rules of probability, determine the probability that the offspring will show YyTT genotype?

OpenStudy (anonymous):

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