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OpenStudy (anonymous):
∫cot^2 5x.dx
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OpenStudy (anonymous):
no ones here to help me eaither
OpenStudy (nikvist):
\[\int\cot^2{5x}dx=\int\frac{\cos^2{5x}}{\sin^2{5x}}dx=\int\frac{1-\sin^2{5x}}{\sin^2{5x}}dx=\int\left(\frac{1}{\sin^2{5x}}-1\right)dx=\]\[=-\frac{1}{5}\cot{5x}-x+C\]
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