Question

solve: solve: @Mathematics

Answer 1

\[\sin^{-1} \frac{12}{13}+\cos ^{-1}\frac{4}{5}+\tan^{-1}\frac{63}{16} \]

Answer 2

its \[\pi\]
very simple but lengthy

Answer 3

5+3+65

Answer 4

@adhirajmajumder : how ?? i want the steps!!!

Answer 5

see ML khanna and JN shrama book pg no 433 (soln)

Answer 6

for your info i don't have such publications

Answer 7

ok then i solv this but can u tell me are u iit engineering student

Answer 8

sorry dhashni did wrong

Answer 9

No am not

Answer 10

ok are u read in any engineering college or pass out

Answer 11

i am yet to pass in

Answer 12

LOL

Answer 13

\[ \sin^{-1} 12/13=\tan^{-1} 12/5\]

Answer 14

and \[\cos^{-1} 4/5 = \tan^{-1} 3/4\]

Answer 15

then \[\tan^{-1} 12/5+\tan^{-1} 3/4+\tan^{-1} 63/16\]
\[\tan^{-1} 12/5+\tan^{-1} 3/4=\pi+\tan^{-1} \left[ (12/5)+(3/4)/1-(12/5)*(3/4) \right]\]
\[\pi+\tan^{-1} (-63/16)\]
\[\pi+\tan^{-1} 63/16-\tan^{-1}63/16 \]
\[\pi\] ans

Answer 16

thanks!!!!

Answer 17

ok pls can u explain me about lol

Answer 18

it is just loud out of laugh

Answer 19

are you an iitian?

Answer 20

no i am appeared to I.I.T

Answer 21

so you are in 12 right now,,,,,,,,,,,,,,,,,,,right???

Answer 22

no i am in b.sc 1st year

Answer 23

oh!!!!
ok

Answer 24

can you pls help me in answering one more question????