Question

Optimization.
Find the Minimum Value for the Function:

f(x)=x^2-ln(x^8), where x>0. @Mathematics

Answer 1

f(x) = x^2 - 8ln(x)
f'(x) = 2x - 8/x

2x-8/x=0
2x=8/x
x^2=4
x=2

Answer 2

f(2) = 2^2 - 8ln2

point is (2, 4-8ln(2))