Question

Logarithmc Equations
logv2 (9x + 5) - logv2 (x^2 - 1) = 2

Answer 1

Please help!

Answer 2

what is v doing above?

Answer 3

IT that sorry!

Answer 4

3,-3/4

Answer 5

by law of logs
logv2 (9x + 5) - logv2 (x^2 - 1)
= log2 [(9x+5)/(x^2-1) = 2
(9x+5)/(x^2-1) = 2^2 = 4
9x+ 5 = 4x^2 - 4
4x^2 - 9x - 9 = 0
(4x + 3 )(x - 3) = 0
x = -3/4 , 3

Answer 6

the only valid root is 3 as -3/4 makes log (9x+5) = log of negative which does not exist

Answer 7

Thank u!