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OpenStudy (fools101):
Logarithmc Equations logv2 (9x + 5) - logv2 (x^2 - 1) = 2
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OpenStudy (fools101):
Please help!
OpenStudy (anonymous):
what is v doing above?
OpenStudy (fools101):
|dw:1321395152056:dw| IT that sorry!
OpenStudy (anonymous):
3,-3/4
OpenStudy (anonymous):
by law of logs logv2 (9x + 5) - logv2 (x^2 - 1) = log2 [(9x+5)/(x^2-1) = 2 (9x+5)/(x^2-1) = 2^2 = 4 9x+ 5 = 4x^2 - 4 4x^2 - 9x - 9 = 0 (4x + 3 )(x - 3) = 0 x = -3/4 , 3
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OpenStudy (anonymous):
the only valid root is 3 as -3/4 makes log (9x+5) = log of negative which does not exist
OpenStudy (fools101):
Thank u!
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