Question

rationalize the denominator
3-sqrtx/2+sqrtx

Answer 1

\[[6-5\sqrt{x}+x]/4-x\]

Answer 2

i dont understand that

Answer 3

if u have got 2 different terms in denominator then u simply multiply both up and down by changing the sings
here u can see: \[[3-\sqrt{x}]/[2-\sqrt{x}]\]=\[[(3-\sqrt{x})(2-\sqrt{x})]/[(2-\sqrt{x})(2+\sqrt{x})]\]

Answer 4

now expand the brackets

Answer 5

oh

Answer 6

this is understandably ?

Answer 7

is that exactly what i type in the answer box?

Answer 8

fly ! when there is on denominator 2+sqrtx so than if you multiply numerator and denominator by 2-sqrtx you will get on denominator tha same like formula a2 -b2 =(a-b)(a+b)

Answer 9

this is ok ?

Answer 10

yes thank you

Answer 11

so than will get on denominator 4-x

Answer 12

ok good luck bye