how to identify the axis of symmetry, the coordnates of the vertex of y=x to the scond power-4

Question

mertsj · Answer

y=x^2-4 is a parabola.  Its vertex is (0,-4)  so its aos is x = 0

anonymous · Answer

so is the axis ofsymmtry always gonnabe 0?

mertsj · Answer

No.  The axis of symmetry always goes through the vertex.  If the vertex would be (3,5) the the aos would be x = 3

anonymous · Answer

how do you  find the veretex

mertsj · Answer

make the equation look like this:    y =ax^2 + bx +c   yours would be
                                                   y = 1x^2 +0x -4
Then the x coordinate of the vertex is the opposite of b over 2a.  In your case it would be the opposite of 0 over 2, which, of course, is 0.  Then find y by plugging 0 into the equation in place of x.  The result will be -4.  That is the y coordinate of the vertex.

cathyangs · Answer

the vertex is -b/2a, for y=ax^2+bx+c

cathyangs · Answer

meant the axis of symmetry XD

anonymous · Answer

so if the question was y=-x^2+4x-1 the axis of symmetry would be -4?

anonymous · Answer

or -2