Question

Use the elimination method to solve the following system of equations.

4x – 2y – z = –5
x – 3y + 2z = 3
3x + y – 2z = –5

Answer 1

damn, you look hot.

add 2nd and 3rd equation:

x - 3y + 2z + 3x + y - 2z = -2

4x - 2y = -2

substitute this into the first equation: -2 - z = -5

therefore z = 3

Answer 2

therefore:

3x + y = 1
4x - 2y = -2

multiply first equation by 2:

6x + 2y = 2

add this to second equation:

10x = 0

therefore x = 0, therefore y = 1

Answer 3

ur missing one

Answer 4

(0, –1, –3)
(0, –1, 3)
(0, 1, 3)
(0, 1, –3)

Answer 5

no, i'm not. i said z = 3

it's (0, 1, 3)

Answer 6

sorry hun i did not see it

Answer 7

im falling asleep

Answer 8

that's ok :)