please solve this one. thanks. 2/3d + 5/2d = 4
d=24/19
do you have a solution?
that is the solution...
okay. thank you :D
you should understand the steps 2/3d + 5/2d = 19/6d and now you have something you can work with easier. You multiply both side by 6d and then you get 19 = 24d and then you divide both sides by 24 to get 19/24 not 24/19.
No. (19/6)d=4 ==> 6(19/6)d=6*4 ==> 19d=24 ==> d=24/19
wolfram alpha it dude your wrong
You can always check your answer by plugging in your solution. So, (2/3)(24/19) + (5/2)(24/19) = 16/19 + 60/19 = 4
d = 19/24
Unfortunately, (2/3)(19/24) + (5/2)(19/24) = 19/36 + 95/48 = 361/144 = 2.5069
omg you are either purposely trying to screw this person up or you are just really dumb
(2/(3(19/24))+(5/(2(19/24))) = 4 You are not even entering the variable into the equation the right way that is why it gave the wrong answer
The right way? It depends on how you specify the equation. I know that people who see \[(2/3)x\]on their paper and type online as \[2/3x\]which you see as \[2/(3x)\] BUT \[2\div3\times x = (2x)\div3\]
I am tired of arguing with you. It is clear you are not understanding order of operations. 2/3*x DOES NOT EQUAL 2/(3x)
2/3 d +5/2 d =4 so than 6 will be the denominator common and will get (4d +15d)/6 = 24/6 4d+15d=24 19d=24 d=24/19
hope so much that is understandably
it depends how you look at the question Jesscama it 2/(3d) + 5/(2d) = 4 or is it (2/3)d + (5/2)d = 4
is it**
ok you are right but for this is necessary using parentheses so when dont us d is considered that is part of numerator
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