Question

@Mathematics I need sum help over here....

Differential Equations :

Method of Undetermined Equations

Example :-

y" - 2y' - 3y = 3x.e^2x

After the auxilirary solvation :-

f(x) = 3x.e^2x

Yh(x) = a1.x1+ a0(e^2x)

My question is , why only the 3x is changed into a1.x1+ a0 ... ??

Why is the e^2x still remains the same . It should be Ce^2x right.....Am I correct...???


Thanxxx in advance....

Answer 1

the differentiation of e^2x is 2x \[e^{x ^{2}}\]