the formula for compound intrest is given by A=P(1+r)^t where A is the total amount of money, P is the principalinvested, r is the intrest rate, and t is the time in years. If $5000 invested at 6.5% intrest compounded annually yields $25,000, for how many years was the money invested?
Given this equation A=P(1+r)^t how do you find t in terms of the other variables?
Well, A/P = (1+r)^t hence taking the natural log of both sides ln(A/P) = ln( (1+r)^t ) = t . ln(1+r) therefore t = ln(A/P) / ln(1+r)
Now substitute all of your values of A, P and r and find t.
can you explain it
which step of the algebra don't you understand: step 1: A/P = (1+r)^t hence taking the natural log of both sides step 2: ln(A/P) = ln( (1+r)^t ) step 3: = t . ln(1+r) therefore step 4: t = ln(A/P) / ln(1+r)
what does r equal
r is the interest rate 6.5%. As ever, you need to express that in decimal format. Hence r = 0.065
so would i substitue like this. ln(5000)/ln(1+1.065)
Almost ln(A/P), not ln(P)
so ln(25,000/5000)/ln(1+0.065)
yes
is the answer 4.69
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