Question

How is this inequality factored?

5/x-8 > 7/6x-1

(5/x-8) - (7/6x-1) > 0

Answer 1

you should first get rid of the denominators in the fractions by first multiplying both sides by x to get:\[5-8x>\frac{7}{6}-x\]then multiply both sides by 6 to get:\[30-48x>7-6x\]can you solve it from there?

Answer 2

-42x+23>0

Then I find the zeros, correct?

Answer 3

your simplification is correct, but there is no "finding of zeros" here. you just need to rearrange the equation to get an inequality for 'x'.

Answer 4

Oh ok, so the zeros are 8 and 1/6

Answer 5

?

Answer 6

\[-42x+23>0\]so:\[23>42x\]rearrange as:\[42x<23\]and then:\[x<23/42\]

Answer 7

this is assuming your original equation was:\[\frac{5}{x}-8>\frac{7}{6x}-1\]

Answer 8

oh, no the original equation is not that....i need to type it correctly.

Answer 9

or was it:\[\frac{5}{x}-8>\frac{7x}{6}-1\]

Answer 10

5 7
- > -
x-8 6x-1

Answer 11

And i have to "Solve the inequality"

Answer 12

ok, so it is:\[\frac{5}{x-8}>\frac{7}{6x-1}\]

Answer 13

Yes, I could not find the division bar

Answer 14

first thing to do would be to multiply both sides by (x-8)(6x-1) to get:\[5(6x-1)>7(x-8)\]then expand to get:\[30x-5>7x-56\]then move all x's to the left-hand-side and all constants to the right-hand-side:\[30x-7x>5-56\]\[23x>-51\]\[x>\frac{51}{23}\]\[x>2\frac{5}{23}\]

Answer 15

sorry I dropped the minus sign in the last two steps

Answer 16

it should end up as:\[x>-2\frac{5}{23}\]

Answer 17

I hope it all made sense to you.

Answer 18

Ok so is the correct solution

\[(-\infty,-51\div23)\]

Answer 19

\[(-\frac{51}{23}, \infty)\]

Answer 20

remember, if z is a whole number and z > -3, it means it cannot be -3, -4, -5, ..., etc. it must be -2, -1, 0, 1, 2, ...

Answer 21

greater than a negative number means it must be bigger than that negative number - which means it must move towards the right on the real number line.

Answer 22

ok, i started over and i just can not get your answer