Question

Calc question. Calc question. @Mathematics

Answer 1

\[0 \lt t \lt 3\]
\[a(t) = 60t\]\[v(t) = 30t^2\]\[s(t) = 10t^3\] right?

Answer 2

right then afterwards gravity takes over, so for
3<t<14
a(t)=-g
v(t)=v(3)-gt
s(t)=s(3)+v(3)t-(1/2)gt^2

Answer 3

oh ok

Answer 4

Where does the -18f/s in 5 seconds come in play at??

Answer 5

so from time
14<t<19
(over the course of 5 seconds)
the velocity falls LINEARLY from v(14) to -18 over the course of 5 seconds. You can get a good old-fashioned linear equation with point-slope form out of that.

Answer 6

so \[y - v(14) = m (x + 18)\]

Answer 7

you need the slope first so
m=[v(14)-(-18)]/5

Answer 8

and then its
v-v(14)=m(t-14)
remember what our variables represent!

Answer 9

So i got
m = -32

Answer 10

v + 178 = -32 (t - 14)

Answer 11

v = -32t + 270

Answer 12

I really don't want to check to make sure that you got the right value for v(14) or s(3) that would require too much time frankly, I'm just outlining the idea. Just try to make sure your answer makes sense. If you get a negative number for max height for instance, you'll know you went wrong somewhere.

Answer 13

Yeah i understand.

Answer 14

Thanks for your help!!

Answer 15

anytime:)