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OpenStudy (anonymous):
Find the absolute extreme values of the function on the interval. f(x)= x^(2/3), [-1, 27] @Calculus1
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OpenStudy (anonymous):
OpenStudy (anonymous):
Derivative: [2/3*x^(-1/3)] Find critical number by making it equal to zero. So, One more critical number at 0. So, -1,0, and 9 will be used. f(-1)=1 f(0)= 0 Absolute Min f(27)= 9 Absolute Max
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