x^2-y^2=2011 x^2-y^2=2011 @Mathematics
(x+y)(x-y) = 2011
Proceed :) please :) sorry
This looks like a circle problem
Its part of a problem from this txml competition
what is the question?
Oh, it's a hyperbola
if you are supposed to find the integer solutions, then notice that 2011 is a prime number, so the only way that \[(x+y)(x-y)=2011\] is if \[x+y=2011,x-y=1\] and you can then solve for x and y
it went something like the sum of integers equals the total distance traveled by plane. The difference between the squares of the two integers = 2011
ok then you are looking for two integers that are one apart and add to 2011 you get 1005 and 1006
or i guess i should say you get 1006 for x and 1005 for y
How on earth did you find that so fast?
How did you find those two numbers?!!
Oh nevermind. I didn't see that 2011 is a prime number
because this is sort of the same as asking for a pythagorean triple where one side is 11 you put \[(x+y)(x-y)=11\] meaning \[x+y=11,x-y=1\] and pretty much solve in your head to get \[x=6,y=5\]
hold on finding the numbers is not the hard part. two numbers that are one apart and add to 2011
the trick is recognizing that that is what you have to do
And this the procedure when a number such as 2011 is a prime number, right?
So if x^2-y^2 = 7, then x = 4 and y = 3?
right
:D
then take \[2\times 4\times 3=24,4^2+3^2=25\] and your right triangle is \[7,24,25\]
Do you guys take the txml?
The what?
i took a taxi once
lol
hahha nevermind
Is txml the new .xml format for excel?
Nah its a math competition by the math league
You're supposed to be at the math league man. What are you doing here? You're not going to win
hahaha no I'm in this after school club and we take these
How did you guys get so good at math? I love it, but I can't get good at it. I suck at problem solving
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