Question

evaluate ∫_(-2)^3〖m^3 〖 (5+ m^4)〗^7 dm〗 evaluate ∫_(-2)^3〖m^3 〖 (5+ m^4)〗^7 dm〗 @Mathematics

Answer 1

\[\int\limits_{-2}^{3}〖m^3 〖 (5+ m^4)〗^7 dm〗\]

Answer 2

let u=5+m^4 -> du= 4m^3dx
x=-2 -> u1= ...
x=3 -> u2=...
1/4 limit from u1 to u2 integration of u^7du

Answer 3

what about the m^3

Answer 4

do u see m^4 is on ur problem, that is du

Answer 5

i meant m^3

Answer 6

du=4m^3dx

Answer 7

are you familiar with wolfram alpha

Answer 8

it shows something completely diff

Answer 9

no

Answer 10

okay, i think u get lost or don't really understand the basic of deri or inter. I'll show it clearly, let me get my calculator.. l0l

Answer 11

I'm eating

Answer 12

Okay,
let u=5+m^4 -> du= 4m^3dx
m=-2 -> u= 5+ (-2)^4= 21
m=3 -> u= 5 +(3)^4=86
\[1/4\int\limits_{21}^{86} u^7du\]
=(1/4)u^8/8 from 21 to 86
Then we have:
[(86)^8] / 32 - [(21)^8] / 32 = ...

Answer 13

Find the answer and replace to find m, that's all

Answer 14

how did you get 56 21definite integral is all i want to know

Answer 15

thanks for the rest

Answer 16

i don't have 56 on my answer

Answer 17

look at m and u, thats how i found the limit

Answer 18

\[\int\limits _{-2}^3m^3 \left(5+m^4\right)^7dm=\frac{2992141448206495}{32}=93504420256452 \]