Question

How do you find the vertex of a trinomial? (e.g. x^2-10x+25) How do you find the vertex of a trinomial? (e.g. x^2-10x+25) @Mathematics

Answer 1

it's easy

Answer 2

Here are the steps to finding the vertex of a quadratic function:

1. Find the first derivative of the function with respect to x, and set it equal to zero.
2. Solve the first derivative for x. Set that value of x to be the x-coordinate of the vertex.
3. Now, using the original quadratic function, find the value of y at the x-coordinate of the vertex.
4. Return the tuple (x,y) corresponding to the vertex of the quadratic function.

Answer 3

WHAT DERIVATIVE

Answer 4

Oh you don't know calculus.... one moment I will give you something else :-D

Answer 5

For a trinomial \[ax^2 + bx + c\]where a, b, and c are coefficients,

the x-coordinate of the vertex is \[-\frac{b}{2a}\]and the y coordinate of the vertex is equal to whatever you get when you plug in what you got for the x-coordinate. in other words: \[a(-\frac{b}{2a})^2 + b(-\frac{b}{2a}) + c\]

Answer 6

AI, you never assume that the person knows calculus if they're asking how to find the vertex of a trinomial. What world are you living in?

Answer 7

I'm pretty sure that if he knew calculus, he wouldn't have even asked how to find a vertex

Answer 8

for the x value, I've just been using the x-intercepts; adding them together and dividing it by two. what do i do for the y-value though?

Answer 9

for the y-value, you simply plug into the equation what you got for the x-value.

Answer 10

both of them?

Answer 11

EVERYONE IS GONNEEE. HELP ME GHOSTS...

Answer 12

just the x-value of the vertex :-P

Answer 13

OK

Answer 14

Coordinate of vertex is (-b/2a, f(-b/2a))
1. calculate -b/2a - it your x coordinate of vertex.
2. Plug tat value into original function instead of x - it's your y-coordinate.

Answer 15

Not Helped