Question

Find the largest interval where the function is changing as requested.

Decreasing f(x)=-sqrt(x+3) @MIT 18.01 Single …

Answer 1

The function is decreasing for
(-∞,0)

Answer 2

the zero point will be x=-3

Answer 3

,,Ullere" why ??? when for x=6 ,f(x)= -3 so for x=13,f(x)=-4 so from this result that the function is decreasing too

Answer 4

Ah, it is because I didn't read the question correctly, I missed the negative sign outside of the brackets. the function would be decreasing for (0,[\infty\])

Answer 5

Wouldn't it be decreasing from [-3,-∞] then ?

Answer 6

Ooops I meant [-3,∞]****

Answer 7

\[f(x)=-(x+3)^{1/2}\] ; \[x \ge-3\]
\[f'(x)=-(1/2)(x+3)^{-1/2}\]
f'(x)=0 ; x=-3
Test Value: x=0
\[f'(0)<0\] so function is decreasing on interval \[(-3,\infty)\]

Answer 8

is first derivative test

Answer 9

I knew it! Thanks

Answer 10

No problem

Answer 11

\[(-3,\infty)\]