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OpenStudy (anonymous):

A cyclist notices that her average speed when she has covered exactly half the total distance of her race is 30 km/h. What should her average speed over the second half of the race be if she wants to finish the race with an average speed of 40 km/h? (a) 45 km/h (b) 50 km/h (c) 60 km/h (d) 54 km/h A cyclist notices that her average speed when she has covered exactly half the total distance of her race is 30 km/h. What should her average speed over the second half of the race be if she wants to finish the race with an average speed of 40 km/h? (a) 45 km/h (b) 50 km/h (c) 60 km/h (d) 54 km/h @Mathematics

OpenStudy (stormfire1):

(30 + 50)/2 = 40....so she needs to go 50 km/h during the second part

OpenStudy (stormfire1):

Note that it only works out this way because the question stated what her average speed was at exactly the midpoint.

OpenStudy (anonymous):

Why divide by 2 ?

OpenStudy (stormfire1):

Because you're taking the average of the two values...since each of the values represents half of the distance

OpenStudy (ash2326):

let the distance be x now for x/2 distance his speed is 30km/h so time taken would be x/60 hours now for average speed of 40km/h his total time is x/40 so other half he has to cover in x/40-x/60 hours x/120 hours so speed for other half is (x/2)/(x/120) that is 60 km/h

OpenStudy (anonymous):

According to answer key it's 50 km/h

OpenStudy (anonymous):

@ash2326, Why would the time taken be x/60 hours ?

OpenStudy (ash2326):

for first half the distance is x/2 km and average speed is 30km/h so time =distance/average speed

OpenStudy (anonymous):

But in second half, average speed changes

OpenStudy (ash2326):

ya, i've calculated it only for first half

OpenStudy (stormfire1):

You can also think of it this way: A course contains 2 exams. You got a 30 on your first exam...what do you need get on your second exam to have a 40 average? 50. I think ash is overcomplicating this one :)

OpenStudy (ash2326):

i've checked it should be 60

OpenStudy (stormfire1):

checked where?

OpenStudy (anonymous):

I think storm fire is right.

OpenStudy (ash2326):

i took a n example suppose the total distance is 120km so first half is covered in 2 hours (60km/30km/h) now if i take average speed 60km/h for second half it takes 1 hour total time 3 hours so average speed 40km/h

OpenStudy (anonymous):

I too did with this same example and got 60 km/h. But I think it's wrong.

OpenStudy (ash2326):

if u take 50 km/h for second half it will take 1.2 hours for second half total time would be 3.2 hours in that case average speed is 37.5kmph

OpenStudy (ash2326):

i tried taking another example of 100km also it's also giving average speed for second half 60km/h

OpenStudy (stormfire1):

The distance is irrelevant here. In my mind, it's simply an equation: \[\frac{30km/h}{2} + \frac{50km/h}{2}=40km/h\]

OpenStudy (ash2326):

yeah the distance is irrelevant i took x and got 60km/h

OpenStudy (stormfire1):

hmm

OpenStudy (stormfire1):

I do see your point. I guess it boils down to whether he should follow the answer key or go with 60km/h :)

OpenStudy (stormfire1):

Ok, I'm sold on 60 km/h...I guess I oversimplified it.

OpenStudy (anonymous):

\[t=\frac{d}{r} \]Let d be the total race distance and r be the required speed to effect an average speed of km/h. Solve the following for r:\[\frac{d/2}{30}+\frac{d/2}{r}=\frac{d}{40}\]\[r=60 \text{ km}/h \]

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