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Mathematics 7 Online
OpenStudy (anonymous):

1 22314 245549 367859 compute the reduced row echelon form. which column vectors of U respond to the free variables? write each of these vectors as a linear combinationof the column vectors corresponding to the lead variables

OpenStudy (across):

I have not the slightest clue how those numbers are separated. :(

OpenStudy (anonymous):

they are all single digits its a 3x6

OpenStudy (anonymous):

which column vectors of A correspond to the lead variables of U? These column vectors for a basis for the column space of A. Write eeach of the remaining column vectors of A as a linear combnationof these basis vectors....part b

OpenStudy (across):

mathematica says\[\begin{bmatrix} 1& 2& 0& 5& -3& 0\\ 0& 0& 1& -1& 2& 0\\ 0& 0& 0& 0& 0& 1 \end{bmatrix}\]it got there in 7 operations

OpenStudy (anonymous):

ok, well lets label the rows 1,2 &3 for now to start subtract 2 times the 1st row from the second row to get the new second row, which i shall call 2'. similarly subtract 3 times the 1st row from the 3rd to get what i will call 3' and you have: 1 2 2 3 1 4 0 0 1 -1 2 1 0 0 1 -1 2 -3 now subtract 3' from 2' to get what i will call 3'' 1 2 2 3 1 4 0 0 1 -1 2 1 0 0 0 0 0 -4 the 3 columns where the first number in that row is non-zero are going to be your not-free variables, so your free variables are the 2nd, 4th, and 5th variables

OpenStudy (anonymous):

you can't solve for any of the variables in terms of the others (which is the final part of the question) unless it is an augmented matrix or is set equal to something. i trust across can explain how to do the rest, since i have to leave for a while.

OpenStudy (anonymous):

how do i write them as a linear combination though

OpenStudy (anonymous):

this one hear

OpenStudy (anonymous):

here

OpenStudy (anonymous):

Lagrangson678

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