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Quadratics! Please help me with this problem!!
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\[1/4x ^{2}+4x-4=0\]
the 1/4 is fraction
you need to apply the quadratic formula with: a=1/4, b=4, and c=-4
I know, its the last part that confuses me
someone solve this please? So i can see what im doing wrong? Please?
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if its the fraction that is confusing you then just multiply the entire equation by 4 to get rid of it and solve:\[x^2+16x-16=0\]
yes its the fraction, so why 4?
because 4 is the denominator of the fraction in:\[\frac{x^2}{4}+4x-4=0\]
for example, suppose we write:\[\frac{3}{4}+\frac{1}{4}=1\]then we can simply multiply both sides by 4 to get:\[3+1=4\]do you understand?
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