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Mathematics 10 Online
OpenStudy (anonymous):

Write the expression in simplest form, assume that the denominator is not 0

OpenStudy (anonymous):

OpenStudy (anonymous):

\[\frac{2a^3-16}{2a^2+4a+8}=\frac{\cancel2(a-2)\cancel{(a^2+2a+4)}}{\cancel2\cancel{(a^2+2a+4)}}=a=2\]

OpenStudy (anonymous):

Once you factor the GCF of 2 in the numerator the a^3-8 is factored as a difference of cubes.

OpenStudy (anonymous):

a=2 is supposed to be a-2 (of course)

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