ln(x^2-x)=ln6
use 1-1 property to solve for x
ln(x^2-x)=ln6
use 1-1 property to solve for x
@Mathematics

Question

ln(x^2-x)=ln6
use 1-1 property to solve for x
 ln(x^2-x)=ln6
use 1-1 property to solve for x
 @Mathematics

across · Answer

What is this 1-1 property? I can easily solve for x, but if I don't do it your way, your teacher will count it wrong.

anonymous · Answer

the 1-1 property states thta if log base a^x= log base a^y, then x=y

across · Answer

What do you think of this?$$\ln(6)=\ln[(-2)^2-(-2)]$$

anonymous · Answer

yep thts one of the answers. thanks!!

anonymous · Answer

There is a theorem such as$$\log(u)=\log(v) \iff u=v$$which means we can equate the arguments of the logs:

ln(x^2-x)=ln6
x^2-x=6                 by the theorem
x^2-x-6=0             set equal to 0
(x-3)(x+2)=0           factor
x=3 or x=-2            solve