Question

ln(x^2-x)=ln6
use 1-1 property to solve for x
ln(x^2-x)=ln6
use 1-1 property to solve for x
@Mathematics

Answer 1

What is this 1-1 property? I can easily solve for x, but if I don't do it your way, your teacher will count it wrong.

Answer 2

the 1-1 property states thta if log base a^x= log base a^y, then x=y

Answer 3

What do you think of this?\[\ln(6)=\ln[(-2)^2-(-2)]\]

Answer 4

yep thts one of the answers. thanks!!

Answer 5

There is a theorem such as\[\log(u)=\log(v) \iff u=v\]which means we can equate the arguments of the logs:

ln(x^2-x)=ln6
x^2-x=6 by the theorem
x^2-x-6=0 set equal to 0
(x-3)(x+2)=0 factor
x=3 or x=-2 solve