Mathematics
20 Online
OpenStudy (anonymous):
x(10x-2)=3 use quadratic formula to solve this.
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OpenStudy (anonymous):
Please help me with this someone? Please, i need to get this done in four hours.
OpenStudy (across):
Expand the expression and rearrange\[10x^2-2x-3=0\]
OpenStudy (across):
I suppose you already know how to complete the square? Seems the purpose of this homework is to train you on it.
OpenStudy (anonymous):
i have what you typed so far
OpenStudy (anonymous):
she didnt teach us to complete the square we skipped that
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OpenStudy (anonymous):
she said we have to solve using quadratic formula
OpenStudy (across):
Oh! Okay.
OpenStudy (across):
Well, you can see that a = 10, b=-2 and c = -3.
OpenStudy (anonymous):
yes
OpenStudy (across):
\[\frac{-(-2)\pm\sqrt{(-2)^2-4(10)(-3)}}{2(10)}\]
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OpenStudy (across):
\[\frac{2\pm\sqrt{4+120}}{20}\]
OpenStudy (across):
\[\frac{1}{10}\pm\frac{\sqrt{31}}{10}\]
OpenStudy (anonymous):
How did you get that
OpenStudy (across):
\[\frac{2}{20}=\frac{1}{10}\]and
OpenStudy (across):
\[\frac{\sqrt{124}}{20}=\frac{\sqrt{4\cdot31}}{20}=\frac{2\sqrt{31}}{20}=\frac{\sqrt{31}}{10}\]
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OpenStudy (anonymous):
\[2+-2\sqrt{31}/10\]
OpenStudy (anonymous):
This part bugs me a lot
OpenStudy (anonymous):
/20 i mean
OpenStudy (across):
\[\frac{2\sqrt{31}}{20}=\frac{2}{20}\sqrt{31}=\frac{1}{10}\sqrt{31}=\frac{\sqrt{31}}{10}\]
OpenStudy (anonymous):
what happened to the other 2?
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OpenStudy (asnaseer):
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