Question

Im doing substitution right now in calcalus and im kinda confused on how to do this problem. {integral}sqrt(x)sin^2(x^(3/2)-1)dx. u=x^(3/2)-1 Im doing substitution right now in calcalus and im kinda confused on how to do this problem. {integral}sqrt(x)sin^2(x^(3/2)-1)dx. u=x^(3/2)-1 @Mathematics

Answer 1

\[\int\limits_{}^{}\sqrt{x}\sin^2(x^{3/2}-1)dx\]
\[u=x^{3/2}-1\]
\[du=(3/2)\sqrt{x}\]
\[(3/2)\int\limits_{}^{}\sin^2(u)du\]
Evaluate this integral and substitute \[u = x^{3/2}\]

Answer 2

so how did you get rid of the sqrt(x)?

Answer 3

It "disappears" because it is part of du.

Answer 4

ahhh ok i see it tyvm