Question

graph the quadratic function. Specify the vertex axis of symmetry, maximum or minimum value and intercepts.
y=x^2+6x-1
I have to solve this bycompleting the square. Can you show me how to do that part?

Answer 1

Find the x-intercepts first.
Then sum of the two x-intercepts divided by 2 = axis of symmetry
Plug the axis of symmetry's x-coordinate into the equation
to find the y-coordinate of the vertex
and the vertex must be minimum value

Answer 2

Do I have to find the square of the quadratic first

Answer 3

What do you mean?

Answer 4

in some of my question it says i need to solve for the square first

Answer 5

(x+3)^2 - 10

Answer 6

But on this one question is does state graph the quadratic function

Answer 7

is this -10 or = 10

Answer 8

(x+3)^2 - 10 = 0

Answer 9

ok I got that far right I just am not sure what to do next. Can you help me?

Answer 10

the vertex is (-3,-10)

Answer 11

so what do I do to find the axis of symmetry?

Answer 12

axis of symmetry is x =-3

Answer 13

is that because it is the smallest

Answer 14

no the axis of symmetry is always = to x = x-coordinate of the vertex

Answer 15

ok

Answer 16

so I must be getting that max and mim mixed up then

Answer 17

equation of parabola is in the form of ax^2 + bx + c

Answer 18

When a is positive,

parabola opens up, which forms a minimum value

Answer 19

When a is negative,

parabola opens down, which forms a maximum value