Question

It is easy to check that for any value of c, function y=x^2+c/x^2 is solution of equation xy'+2y=4x^2, (x>0).

Find the value of c for which the solution satisfies the initial condition
y(6)=2.

Answer 1

this is a calculus problem . i just don't know how to go by solving it while putting the initial conditions in

Answer 2

take the derivative and you solve for y', take the y' to the second

Answer 3

it seems not right

Answer 4

is this for the 2nd equation only or both

Answer 5

what seems not right?! im confused

Answer 6

maybe: 6^2+c/(6^2)=2 c=-1224

Answer 7

yeah that is the right answer