Question

Someone pushes a 15 kg object with a force of 500N for a distance of 1 meter. The object started
from rest and 2 meters from the block is a spring with k = 20 N/m. The object slides on a surface with
coefficient of friction .2. How far is the spring compressed by the object Someone pushes a 15 kg object with a force of 500N for a distance of 1 meter. The object started
from rest and 2 meters from the block is a spring with k = 20 N/m. The object slides on a surface with
coefficient of friction .2. How far is the spring compressed by the object @Mathematics

Answer 1

Fnet = Fapp - Ff
Fnet = 500 - (150)(.2)
Fnet =470 N

F = ma
470 = 15 a
a= 470/15
a= 31.33333

Vf = (2(31.33333)1)^.5
Vf = 7.91622764

.5mv^2 = .5kx^2
mv^2 = kx^2
15(7.91622764)^2 = 20x^2
x = ((15*(7.91622764) ^2) / 20 )^.5
x = 6.85565424m

Hope it works.. =)