Question

Solve the equation below. Please show all of your work.
log2(1/64)=1/3-x

Solve the equation below. Please show all of your work.
log2(1/64)=1/3-x

@Mathematics

Answer 1

x= -log2(1/64) + 1/3

x= 19/3

Answer 2

how did you get this?

Answer 3

because loga +logb=log(a*b) so this is property of logaritms

Answer 4

but i think that this not is correct because
so 1/64 = 1/2(6) like 2 on exponent 6
so log2(

Answer 5

so will be log2(2) on exponent minus 6

Answer 6

than will be -6log2(2) = -6

Answer 7

than -6=1/3 -x
so -18=1-3x
-19=-3x
19=3x
x=19/3

Answer 8

it's all numbers... log2(1/64) is a number (-6) just like 1/3 is a number (.3333)

think of it as -6=.333-x and solve for x

Answer 9

log2(1/64) = log(1/64)/log(2)