Question

need help on the attachment @Calculus1

Answer 1

\[\int_{0}^{1}\pi(\sqrt[4]{x})^2dx-\int_{0}^{1}\pi(x^4)^2dx\]

Answer 2

how come but side are the same

Answer 3

What do you mean?

Answer 4

oh, wait my eyes are playing tricks on me I thought I saw a square root in the right integral

Answer 5

Yeah, integrals will do that to your eyes. :P

Answer 6

I got 7pi/9 is that what you got?

Answer 7

They're subtracting.

Answer 8

\[\pi\int_{0}^{1}\sqrt{x}dx=\frac{2}{3}\pi\left[x^{\frac{3}{2}}\right]_{0}^{1}=\frac{2}{3}\pi,\]\[\pi\int_{0}^{1}x^8dx=\pi\left[\frac{1}{9}x^9\right]_{0}^{1}=\frac{1}{5}=\frac{1}{9}\pi,\]\[\frac{2}{3}\pi-\frac{1}{9}\pi=\frac{5}{9}\pi.\]

Answer 9

dang I integrated wrong by different number number to the exponents beside the number 1

Answer 10

oops! I forgot "adding" in between by and different