Question

need help on the attachment @Calculus1

Answer 1

ok i remember this one. we already found the points of intersection right?

Answer 2

yes

Answer 3

lower one was -2 if i remember and biggest one was 1

Answer 4

so it would be choice 2

Answer 5

if my memory is correct

Answer 6

points were -2,0,1

Answer 7

in actuality if you were going to compute this you would have to break up the integral into two parts

Answer 8

right you are. so if you actually had to compute this, you would have to integrate from -2 to 0 and then from 0 to 1 because the functions switch places at 0

Answer 9

but the question has the absolute value in the integrand, so answer is choice 2
now if you have to compute this in the next question you will have to compute two separate integrals

Answer 10

next is question is asking to Calculate the area of this shaded region.

Answer 11

so to anticipate the next question, it will be
\[\int_{-2}^0 1-x-(1+x=x^2-x^3)dx +\int_0^1(1+x-x^2-x^3)-(1-x)dx\]

Answer 12

a) area =35/12
sq. units
b) area =10/3
sq. units
c) area =9/4
sq. units
d) area =37/12
sq. units
e) area =17/6
sq. units

Answer 13

step number one is to actually do the subtraction and step number two is to integrate. that is all
you have to make two integrals. first one will be
\[\int-2x+x^2+x^3 dx\] second will be
\[\int 2x-x^2-x^3dx\]

Answer 14

what happen to the endpoints???

Answer 15

need help Calculating the area of the shaded region.

Answer 16

I see that. Why don't you just use a calc?

Answer 17

huh?

Answer 18

???

Answer 19

If you really want to learn this get skype so I can show you

Answer 20

are you jk or are you serious?

Answer 21

What do you think?