@ How many moles of carbon dioxide will be formed upon the complete reaction of 0.424 moles glucose sugar (C6H12O6) with excess oxygen gas? I got the balanced equation so far; 1C6H1206+6O2-->6CO2+12H20
You've got most of the work done already in balancing the equation, good job! All you need to do is use the numbers in front of each molecule to find the ratio of moles. You've got:\[1C_6H_{12}O_6 : 6CO_2\] which means that for every 1 mole of glucose, you get 6 moles of carbon dioxide. You don't have 1 mole of glucose though, you have 0.424! How many moles of carbon dioxide will that yield?
Um is there a formula or a step that needs to be used. Such as the dinemsional analysis
Kind of. You can use the standard ratio formula. The ratio of 1:6, must equal the ratio of 0.424:x, where x is the number of moles of carbon dioxide. \[\frac{1}{6}=\frac{0.424}{x}\]
So you just plugged in the numbers and so I need to divide 6 by 0.424
Multiply, not divide :)
2.54
Yarp
Thanks
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