Question

physics help @NIT study group

Answer 1

anone??

Answer 2

yes

Answer 3

???

Answer 4

y a i need help

Answer 5

A cricket ball is hit at 45 degree to horizontal with a K.E. of K.The KE at highest point is???

Answer 6

KE = 0.5 m v^2

the velocity can be broken into orthogonal components: vertical and horizontal.
Neglecting air resistance, the horizontal component is constant. The vertical component of the velocity is zero at the peak.

So Vh= V cos(45) = V/sqrt(2)
and KEp (for peak) = 0.5 m V^2/2 or KE/2

Answer 7

k
phi
can u do a help??

Answer 8

on what?

Answer 9

wel can u come in twiddla ??i will giv link

Answer 10

plssss

Answer 11

ok

Answer 12

thx a lot

Answer 13

from the conservation of energy::
total mechanical energy at initial=total mechanical energy final
k+0=k'+mgHmax
k=k'+mg*u^2(sin^2(45))/2g=>k=k'+1/2(1/2mu^2)..here u is initial velocity(let)
=>k=k'+k/2=>k'=k/2..answer