Question

How do I put this in slope intercept form: -3x + 2y = 8 ?

Answer 1

Solve for y by bringing all other terms to the other side of the equation.

2y = 8 + 3x

y = 4 + 3/2 x

Simple, really.

Answer 2

-3x + 2y = 8
2y = 8 + 3x
y = 1.5x + 4

Answer 3

the question at this stage doesnt tend to be "how" to put it into slope int form; but rather, what is slope int form ....

Answer 4

I've never referred to it as "slope intercept" form, but I'm assuming it's the method we learnt for constructing simple graphs back... whenever it was, where curves take the equation y = mx + c with m being the slope and c the intercept?

Answer 5

yep, hence the name, slope intercept form

Answer 6

I've never heard that called anything other than slope intercept form.

Answer 7

The only curve sketching I've done in recent times involves calculus, so I don't recall what I've ever referred to it as - other than "y = mx + c." Not that I'm saying "slope intercept form" doesn't make sense or is a bad name.

Answer 8

Any one of you care to explain how I can plot this?

Answer 9

The intercept (in the context, the y-intercept) is where it crosses the y axis, and the slope is the value of m. So for every value of x, y is going to be m*x (starting at c). If that makes sense.

Answer 10

The "c" is the value of the equation when x = 0, so you know that is the y intercept.

The "x" is linear so you know that you're looking at a line, not a quadratic or some other polynomial.

The coefficient in front of the x shows the "rise over the run."

In totally non-mathematic terms.

Answer 11

In this case the intercept (c) is 4, so plot a point on the y-axis at (0,4). Then - depending on your scale, but generally simple hand-drawn graphs increment by 1 - at x = 1, plot a point at 1.5x + 4 = 1.5*1 + 4 = 1.5 + 4 = 5.5 so (1,5.5). Then at x = 2, y = 1.5*2 + 4 = 3 + 4 = 7, so (2,7). And so on and so forth until you get as far as necessary.